Exercise 2.4

Question 1:
Verify that the numbers given alongside of the cubic polynomials below are their zeroes. Also verify the relationship between the zeroes and the coefficients in each case:




(i)







Therefore,

 , 1, and −2 are the zeroes of the given polynomial.
Comparing the given polynomial with ,

 we obtain a = 2, b = 1, c = −5, d = 2



Therefore, the relationship between the zeroes and the coefficients is verified.
(ii)









Therefore, 2, 1, 1 are the zeroes of the given polynomial.
Comparing the given polynomial with ,

we obtain a = 1, b = −4, c = 5, d = −2.
Verification of the relationship between zeroes and coefficient of the given polynomial


Multiplication of zeroes taking two at a time = (2)(1) + (1)(1) + (2)(1) =2 + 1 + 2 = 5

Multiplication of zeroes = 2 × 1 × 1 = 2

Hence, the relationship between the zeroes and the coefficients is verified.


Question 2:
Find a cubic polynomial with the sum, sum of the product of its zeroes taken two at a time, and the product of its zeroes as 2, − 7, − 14 respectively.

Let the polynomial be
  

 and the zeroes be
.
It is given that


If a = 1, then b = −2, c = −7, d = 14
Hence, the polynomial is
.
Question 3:
If the zeroes of polynomial
  

are,

 find a and b.


Zeroes are ab, a + a + b
Comparing the given polynomial with ,

 we obtain
p = 1, q = −3, r = 1, t = 1


The zeroes are .


Hence, a = 1 and b =
 or
 .


Question 4:
If two zeroes of the polynomial
  

are, 
find other zeroes.
Given that 2 +
and 2­­-
 are zeroes of the given polynomial.
Therefore
= x2 + 4 ­­− 4x − 3
= x2 ­− 4x + 1 is a factor of the given polynomial
For finding the remaining zeroes of the given polynomial, we will find the quotient by dividing

 by x2 ­− 4x + 1.



Clearly,
=

It can be observed that

is also a factor of the given polynomial.
And
 =
Therefore, the value of the polynomial is also zero when
or
Or x = 7 or −5
Hence, 7 and −5 are also zeroes of this polynomial.






Question 5:
If the polynomial
  


is divided by another polynomial

the remainder comes out to be x + a, find k and a.

By division algorithm,
Dividend = Divisor × Quotient + Remainder
Dividend − Remainder = Divisor × Quotient

will be perfectly divisible by
 .
Let us divide
 by



It can be observed that

 will be 0.
Therefore,

= 0 and

= 0
For
= 0,
2 k =10
And thus, k = 5
For
= 0
10 − a − 8 × 5 + 25 = 0
10 − a − 40 + 25 = 0
− 5 − a = 0
Therefore, a = −5
Hence, k = 5 and a = −5